Optimal. Leaf size=87 \[ \frac{10 a^2 \tan (c+d x)}{3 d}+\frac{2 a^2 \tanh ^{-1}(\sin (c+d x))}{d}-\frac{a^4 \tan (c+d x)}{3 d (a-a \cos (c+d x))^2}-\frac{2 a^2 \tan (c+d x)}{d (1-\cos (c+d x))} \]
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Rubi [A] time = 0.297441, antiderivative size = 87, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.381, Rules used = {3872, 2869, 2766, 2978, 2748, 3767, 8, 3770} \[ \frac{10 a^2 \tan (c+d x)}{3 d}+\frac{2 a^2 \tanh ^{-1}(\sin (c+d x))}{d}-\frac{a^4 \tan (c+d x)}{3 d (a-a \cos (c+d x))^2}-\frac{2 a^2 \tan (c+d x)}{d (1-\cos (c+d x))} \]
Antiderivative was successfully verified.
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Rule 3872
Rule 2869
Rule 2766
Rule 2978
Rule 2748
Rule 3767
Rule 8
Rule 3770
Rubi steps
\begin{align*} \int \csc ^4(c+d x) (a+a \sec (c+d x))^2 \, dx &=\int (-a-a \cos (c+d x))^2 \csc ^4(c+d x) \sec ^2(c+d x) \, dx\\ &=a^4 \int \frac{\sec ^2(c+d x)}{(-a+a \cos (c+d x))^2} \, dx\\ &=-\frac{a^4 \tan (c+d x)}{3 d (a-a \cos (c+d x))^2}+\frac{1}{3} a^2 \int \frac{(-4 a-2 a \cos (c+d x)) \sec ^2(c+d x)}{-a+a \cos (c+d x)} \, dx\\ &=-\frac{2 a^2 \tan (c+d x)}{d (1-\cos (c+d x))}-\frac{a^4 \tan (c+d x)}{3 d (a-a \cos (c+d x))^2}+\frac{1}{3} \int \left (10 a^2+6 a^2 \cos (c+d x)\right ) \sec ^2(c+d x) \, dx\\ &=-\frac{2 a^2 \tan (c+d x)}{d (1-\cos (c+d x))}-\frac{a^4 \tan (c+d x)}{3 d (a-a \cos (c+d x))^2}+\left (2 a^2\right ) \int \sec (c+d x) \, dx+\frac{1}{3} \left (10 a^2\right ) \int \sec ^2(c+d x) \, dx\\ &=\frac{2 a^2 \tanh ^{-1}(\sin (c+d x))}{d}-\frac{2 a^2 \tan (c+d x)}{d (1-\cos (c+d x))}-\frac{a^4 \tan (c+d x)}{3 d (a-a \cos (c+d x))^2}-\frac{\left (10 a^2\right ) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{3 d}\\ &=\frac{2 a^2 \tanh ^{-1}(\sin (c+d x))}{d}+\frac{10 a^2 \tan (c+d x)}{3 d}-\frac{2 a^2 \tan (c+d x)}{d (1-\cos (c+d x))}-\frac{a^4 \tan (c+d x)}{3 d (a-a \cos (c+d x))^2}\\ \end{align*}
Mathematica [B] time = 1.67115, size = 228, normalized size = 2.62 \[ \frac{a^2 (\cos (c+d x)+1)^2 \sec ^4\left (\frac{1}{2} (c+d x)\right ) \left (-\cot \left (\frac{c}{2}\right ) \csc ^2\left (\frac{1}{2} (c+d x)\right )+6 \left (\frac{\sin (d x)}{\left (\cos \left (\frac{c}{2}\right )-\sin \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right ) \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}-2 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+2 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )+\csc \left (\frac{c}{2}\right ) \sin \left (\frac{d x}{2}\right ) (-(7 \cos (c+d x)-8)) \csc ^3\left (\frac{1}{2} (c+d x)\right )\right )}{24 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.059, size = 140, normalized size = 1.6 \begin{align*} -{\frac{10\,{a}^{2}\cot \left ( dx+c \right ) }{3\,d}}-{\frac{{a}^{2}\cot \left ( dx+c \right ) \left ( \csc \left ( dx+c \right ) \right ) ^{2}}{3\,d}}-{\frac{2\,{a}^{2}}{3\,d \left ( \sin \left ( dx+c \right ) \right ) ^{3}}}-2\,{\frac{{a}^{2}}{d\sin \left ( dx+c \right ) }}+2\,{\frac{{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}-{\frac{{a}^{2}}{3\,d \left ( \sin \left ( dx+c \right ) \right ) ^{3}\cos \left ( dx+c \right ) }}+{\frac{4\,{a}^{2}}{3\,d\sin \left ( dx+c \right ) \cos \left ( dx+c \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.00846, size = 153, normalized size = 1.76 \begin{align*} -\frac{a^{2}{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{2} + 1\right )}}{\sin \left (d x + c\right )^{3}} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + a^{2}{\left (\frac{6 \, \tan \left (d x + c\right )^{2} + 1}{\tan \left (d x + c\right )^{3}} - 3 \, \tan \left (d x + c\right )\right )} + \frac{{\left (3 \, \tan \left (d x + c\right )^{2} + 1\right )} a^{2}}{\tan \left (d x + c\right )^{3}}}{3 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.67692, size = 396, normalized size = 4.55 \begin{align*} -\frac{10 \, a^{2} \cos \left (d x + c\right )^{3} - 4 \, a^{2} \cos \left (d x + c\right )^{2} - 11 \, a^{2} \cos \left (d x + c\right ) - 3 \,{\left (a^{2} \cos \left (d x + c\right )^{2} - a^{2} \cos \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) \sin \left (d x + c\right ) + 3 \,{\left (a^{2} \cos \left (d x + c\right )^{2} - a^{2} \cos \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) \sin \left (d x + c\right ) + 3 \, a^{2}}{3 \,{\left (d \cos \left (d x + c\right )^{2} - d \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.4944, size = 140, normalized size = 1.61 \begin{align*} \frac{12 \, a^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 12 \, a^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{12 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1} - \frac{15 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3}}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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